Load case combinations according to EC

SCIA Engineer makes no distinction between primary and secondary variable load case. The algorithm takes one load case (in turn) as the primary one and all the others are considered secondary. The coefficients Psi0 are assigned accordingly. Doing this in turns, all the possible combinations are exploited. No combination should contain two variable load cases with the full coefficient 1.5 (one of them is always reduced by the corresponding Psi0).

It may happen, under some special circumstances, that this approach is not the most economical one (if the primary load is small (insignificant) and the secondary one is large - there is the difference if the coefficient Psi0=0.5 is applied to the large load or the small one). However, this is based on the assumption that the large load is usually taken as the primary one.

Let us consider the following load cases, groups and combinations.

Load cases:

Name

Description

Action type

Load group

Load type

Specification

Direction

Duration

Master load case

LC1

self weight

Permanent

LG1

Self weight

 

-Z

 

 

LC2

live load (20 kNm)

Variable

LG2

Static

Standard

 

Long

None

LC3

snow load (10 kNm)

Variable

LG3

Static

Standard

 

Long

None

Load groups:

Name

Load

Relation

Coeff 2

LG1

Permanent

 

 

LG2

Variable

Standard

Cat E: Storage

LG3

Variable

Standard

Snow load H < 1000 m a.s.l.

Combinations:

Name

Description

Type

Load cases

Coeff [1]

CO1

(1)

EN - ULS Fundamental (STR)

LC1 - self weight

1.00

 

 

 

LC2 - live load (20 kNm)

1.00

 

 

 

LC3 - snow load (10 kNm)

1.00

CO2

(7)

EN - ULS Accidential - Psi 1

LC1 - self weight

1.00

 

 

 

LC2 - live load (20 kNm)

1.00

 

 

 

LC3 - snow load (10 kNm)

1.00

CO3

(1)

EN - ULS Accidential - Psi 2

LC1 - self weight

1.00

 

 

 

LC2 - live load (20 kNm)

1.00

 

 

 

LC3 - snow load (10 kNm)

1.00

Let us use the following combinations setup:

image\LCC_EN_Setup.gif

 

We get the following envelope combinations:

C1.1

(118)

Envelope – ultimate

LC1 – self weight

1.35

C1.2

(119)

Envelope – ultimate

LC1 – self weight

LC2 - live load (20 kNm)

LC3 – snow load (10 kNm)

1.35

1.50

0.75

C1.3

(120)

Envelope – ultimate

LC1 – self weight

LC2 - live load (20 kNm)

LC3 – snow load (10 kNm)

1.00

1.50

0.75

C1.4

(121)

Envelope – ultimate

LC1 – self weight

LC2 - live load (20 kNm)

LC3 – snow load (10 kNm)

1.35

1.50

1.50

C1.5

(122)

Envelope – ultimate

LC1 – self weight

LC2 - live load (20 kNm)

LC3 – snow load (10 kNm)

1.00

1.50

1.50

C2.1

(123)

Envelope – ultimate

LC1 – self weight

1.00

C2.2

(124)

Envelope – ultimate

LC1 – self weight

LC2 - live load (20 kNm)

LC3 – snow load (10 kNm)

1.00

0.90

0.00

C2.3

(125)

Envelope – ultimate

LC1 – self weight

LC2 - live load (20 kNm)

LC3 – snow load (10 kNm)

1.00

0.80

0.20

C3.1

(126)

Envelope – ultimate

LC1 – self weight

1.00

C3.2

(127)

Envelope – ultimate

LC1 – self weight

LC2 - live load (20 kNm)

LC3 – snow load (10 kNm)

1.00

0.80

0.00

C3.3

(128)

Envelope – ultimate

LC1 – self weight

LC2 - live load (20 kNm)

LC3 – snow load (10 kNm)

1.00

0.80

0.00

Let us review the already stated:

LC1 – permanent => LG 1

LC2-variable (live load (20kNm)) => LG2 (Cat E : Storage) => from setup: Psi 0 =1.0, Psi1=0.9, Psi2=0.8

LC3–variable (snow load (10kNm) ) => LG3 (Snow load H < 1000 m a.s.l.") => from setup: Psi 0 =0.5, Psi1=0.2, Psi2=0.0

Combination C01 (EN - ULS Fundamental(STR)) : LC1+LC2+LC3

We use Eq.6.10

image\LCCombinations_Eq_610.gif

It is not specified at the load case if it is the primary or secondary load case. Therefore, always one load case (group) in turn is taken as the primary one and the rest is considered secondary. This is repeated until all the load cases are used for the primary one.

We get the following combinations:

First of all, we get the combination with just the permanent load cases

C1.1 1.35 * LC1

Secondly, one variable load case is taken as primary one (1.5) and the rest as secondary (1.5 * Psi0) + the permanent load is either favourable (1.0) or unfavourable (1.35)

The combinations obtained are:

Permanent load case LC1 is unfavourable (1.35) and LC2 is the primary load.

C1.2 1.35*LC1 + 1.5*LC2 + 1.5*Psi0*LC3 = 1.35*LC1 + 1.5*LC2 + (1.5*0.5)*LC3 = 1.35*LC1 + 1.5*LC2 + 0.75*LC3

(Psi0 = 0.5; LG3 is (Snow load H < 1000 m a.s.l.") )

Permanent load case LC1is favourable (1.00) and LC2 is the primary load.

C1.3 1.0*LC1 + 1.5*LC2 + 1.5*Psi0*LC3 = 1.0*LC1 + 1.5*LC2 + (1.5*0.5)*LC3 = 1.0*LC1 + 1.5*LC2 + 0.75*LC3

(Psi0 = 0.5; LG3 is (Snow load H < 1000 m a.s.l.") )

Permanent load case LC1 is unfavourable (1.35) and LC3 is the primary load.

C1.4 1.35*LC1 + 1.5*LC3 + 1.5*Psi0*LC2 = 1.35*LC1 + 1.5*LC3 + (1.5*1.0)*LC2 = 1.35*LC1 + 1.5*LC3 + 1.5*LC2

(Psi0 = 1.0; LG2 is Category E )

Permanent load case LC1 is favourable (1.00) and LC3 is the primary load.

C1.5 1.0*LC1 + 1.5*LC3 + 1.5*Psi0 = 1.0*LC1 + 1.5*LC3 + (1.5*1.0)*LC2 = 1.0*LC1 + 1.5*LC3 + 1.5*LC2

(Psi0 = 1.0; LG2 is Category E )

Then we have combinations C2 and C3 that are created using these rules:

image\LCCombinations_Eq_611b.gif

The choice between 1,l or 2,l is done by the user. Default is 1,l.

C02 - EN - ULS Accidental - Psi 1 : LC1+LC2+LC3

First of all, we get the combination with just the permanent load cases

C2.1 1.0 * LC1

Second, the combination rule applies Psi1 to one load case and Psi2 to the other one.

C2.2 1.0 * LC1 + Psi1*LC2 + Psi2*LC3 = 1.0 * LC1 + 0.9*LC2 + 0.0*LC3

C2.3 1.0 * LC1 + Psi2(LG2) *LC2 + Psi1(LG3)*LC3 = 1.0 * LC1 + 0.8*LC2 + 0.2*LC3

C03 - EN - ULS Accidental - Psi 2 : LC1+LC2+LC3

First of all, we get the combination with just the permanent load cases

C3.1 1.0 * LC1

Second, the combination rule applies Psi1 to one load case and Psi2 to the other one.

C3.2 1.0 * LC1 + Psi2*LC2 + Psi2*LC3 = 1.0 * LC1 + 0.8*LC2 + 0.0*LC3

C3.3 1.0 * LC1 + Psi2(LG2) *LC2 + Psi2(LG3)*LC3 = 1.0 * LC1 + 0.8*LC2 + 0.0*LC3

In addition, the combinations setup dialogue makes it possible to say that instead of Eq.6.10, formulas Eq.6.10a & Eq.6.10b should be used and the rule for the combination is:

image\LCCombinations_Eq_610b.gif

image\LCCombinations_Eq_610a.gif

The choice between Eq.6.10 and (Eq.6.10a & Eq.6.10.b) is done in the National Annex.

The default is Eq.6.10.