Design of shear reinforcement for shear forces

 

As was mentioned above, there exists general concept of “strut-and-tie” model for the prediction of shear effects in concrete. In this model, the top compression and bottom tensile members represent the compressive concrete and tensile reinforcement, respectively. The procedure for design can be represented by diagram below:

The formulas which are used for the calculation of each component of this model are the following.

Generally, there are two possibilities for calculation of shear capacity of concrete dependently on existence of cracks in bending:

Shear concrete capacity in region cracked in bending – formula 6.2.a,b in EN 1992-1-1

VRd,c = [CRd,c ∙ k ∙ (100 ∙ ρl ∙ fck)1/3 + k1 ∙ σcp] ∙ bw ∙ d

VRd,c,min = (νmin + k1 ∙ σcp) ∙ bw ∙ d

Shear concrete capacity in region uncracked in bending – clause 12.6.3(3) in EN 1992-1-1

VRd,c = fcvd ∙ Acc / k12.6.3

Additionally, there is calculated maximal shear force (VEd,max) without reduction by β for member where load is applied in the upper side of the member (see formula 6.5 in EN 1992-1-1).

VEd,max = 0,5 ∙ bw1 ∙ d ∙ ν ∙ fcd

Maximal capacity of concrete compressive strut (VRd,max ) is determined according to formula 6.9 in EN 1992-1-1, because as has been mentioned before, the angle of stirrups θ is always perpendicular to member axis.

VRd,max = (αcw ∙ bw1 ∙ z ∙ ν1 ∙fcd) / (cot θ + tan θ)

Statically required cross-sectional area of the shear reinforcement per meter is calculated from the formula 6.13 in EN 1992-1-1

Aswm,req = Asw,req / sl,req = VEd / (z ∙ fywd ∙ (cot θ + cot α) ∙ sin α)

Design value of shear force sustained by shear reinforcement (VRd,s) is calculated according to formula 6.13 in EN 1992-1-1

VRd,s = Asw / s ∙ z ∙ fywd ∙ (cot θ + cot α) ∙ sin α

Final design value of shear force (VRd) carried by member is calculated based on the following formulas depending on type of member and area of shear reinforcement.

VRd = VRd,c ≤ min(VRd,max, VEd,max) + Vtd + Vccd

VRd = VRd,s + Vtd + Vccd ≤ min(VRd,max, VEd,max) + Vtd + Vccd

where

VEd

resultant of shear force

VEd = √(VEd,y2 + VEd,z2)

VEd,y(z) shear force in direction of y(z) axis of LCS
VRd,c the design shear resistance of the member without shear reinforcement
σct,max maximal tensile strength in uncracked cross-section
VRd,c,min the minimal value of design shear resistance of the member without shear reinforcement
CRd,c coefficient for calculation VRd,c loaded from Manager for National annexes
k

coefficient of effective height of cross-section

k = 1 + √(200 / d) ≤ 2

ρl

ratio of tensile reinforcement

ρl = Asl / (bw ∙d) ≤ 0,02

fck characteristic compressive cylinder strength of concrete
k1 coefficient for calculation VRd,c loaded from Manager for National annexes
σcp

stress caused by axial force (NEd > 0 for compression)

σcp = NEd / Ac ≤ 0,2 ∙ fcd

bw the smallest width of the cross-section in tensile area of cross-section perpendicular to direction of resultant shear force, see "Width of cross-section for shear check"
d effective depth of cross-section recalculated to direction of shear forces resultant, see "Effective depth of cross-section for shear check"
Asl statically required tensile area of reinforcement, see "Design of longitudinal reinforcement"
NEd the axial force in the cross-section due to loading or prestressing.
Ac the area of concrete cross section
fcd design value of concrete compressive strength
νmin Coefficient of minimum value of shear resistance of the member without shear reinforcement loaded from Manager for National annexes,see equation 6.3N in EN 1992-1-1
fcvd

the concrete design strength in shear and compression, see equations 12.5 and 12.6 in EN 1992-1-1

if σccp ≤ σc,lim: fcvd = √(fctd2 + σccp ∙ fctd)

if σccp > σc,lim: fcvd = √(fctd2 + σccp ∙ fctd - ((σccp - σc,lim) / 2)2)

fctd design axial tensile strength of concrete
σccp

normal (axial) stress of uncracked cross-section

σccp = NEd / Acc

σc,lim

limit value of stress caused by axial force, see equations 12.7 in EN 1992-1-1

σc,lim = fcd - 2 ∙ √(fctd ∙ (fctd + fcd))

Acc compressed concrete area for uncracked cross-section
VEd,max maximum value of shear force resultant calculated without reduction by coefficient β, see clause 6.2.2(6) in EN 1992-1-1
bw1 minimum width of cross-section between tension and compression chord perpendicular to direction of shear force, see "Width of cross-section for shear check"
ν strength reduction factor for concrete cracked in shear loaded from Manager for National annexes, see equation 6.6N in EN 1992-1-1
VRd,max the design value of the maximum shear force which can be sustained by the member, limited by crushing of the compression struts
αcw coefficient taking into account state of the stress in the compression chord, see note 3 in clause 6.2.3(3) in EN 1992-1-1. The value 1 is always taken into account for non -prestressed structures
z inner lever arm of cross-section recalculated to direction of shear forces resultant, see "Inner lever arm for shear check"
ν1

strength reduction factor for concrete cracked in shear loaded from Manager for National annexes, see note 1 and 2 in clause 6.2.3(3) in EN 1992-1-1

if σswd > 0,8 ∙ fywk : ν1 = ν

if σswd ≤ 0,8 ∙ fywk and fck ≤ 60 MPa: ν1 = 0,6

if σswd ≤ 0,8 ∙ fywk and fck > 60 MPa: ν1 = 0,9 - fck / 200 > 0,5

θ Angle between concrete compression strut and beam axis perpendicular to the shear force, see "Angle between concrete compression strut and beam axis"
VRd,s design value of the shear force which can be sustained by the yielding shear reinforcement
Aswm.req Statically required cross-sectional area of the shear reinforcement per meter
Asw the cross-sectional area of the shear reinforcement calculated from inputted parameters in design default, see "Design Defaults"

Asw = ns ∙ 0,25 ∙ π ∙ dss2

dss diameter of stirrups loaded from Concrete setting or Concrete data, see "Design Defaults"
ns number of cuts (shear links) loaded from Concrete setting or Concrete data, see "Design Defaults"
sl.req

the spacing of the stirrups in longitudinal direction

sl,req = Asw / Aswm,req

fywd

the design yield strength of the shear reinforcement

α angle of shear reinforcement loaded from Concrete setting or Concrete data, see "Design Defaults". This angle for column is 90 °
fywk characteristic yield strength of the shear reinforcement
Vtd the design value of the shear component of the force in the tensile reinforcement, in the case of an inclined tensile chord
Vccd the design value of the shear component of the force in the compression area, in the case of an inclined compression chord

For member with inclined chords the additional forces haves to be taken into account for shear check according to clause 6.2.1(1). The calculation is prepared for taking into account also inclined chords. Nevertheless the calculation itself is not implemented yet. The partial components are explained in the following figure.

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